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An aqueous solution containing barium iodide (bai2) is electrolyzed in a cell containing inert electrodes. what are the products at the anode and cathode?

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Answer is: hydrogen (cathode), iodine (anode).
The balanced oxidation half reaction: 2I⁻(aq) → I₂(s) + 2e⁻.
Iodine is oxidized (lost electrons) from -1 to neutral charge (0).
The balanced reduction half-reaction: 2H₂O(l) + 2e⁻ → H₂(g) + 2OH⁻.
Hydrogen is reduced (gain electrons) from +1 to neutral charge.

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