Respuesta :
sinA=BC/AB =>BC=sin75*12
cosA=AC/AB =>AC=cos75*12
the area is (1/2)AC*AB=(1/2)sin75*12*cos75*12=18
cosA=AC/AB =>AC=cos75*12
the area is (1/2)AC*AB=(1/2)sin75*12*cos75*12=18
