Respuesta :

wuzzleluver
With a point (h,k) an equation of a line in point-slope form is y-k=m(x-h).

A(-2, -1)= (X1,Y1)
B(6,5)= (X2,Y2)

Slope = ((Y2-Y1)/(X2-X1))
m= ((5-(-1))/(6-(-2))= (5+1)/(6+2)= 6/8= 3/4
m= 3/4

ANSWER: 

When using point B, (6,5) = (h,k)
 y-k=m(x-h)
 y-5=(3/4)(x-6)

None of the equations using point A's cooridinates for h and k would work because A(-2,-1) has negative values.  These negative would alter the subtraction in the equation to addition for example a correct equation for point A would be:  y+1=(3/4)(x+2).

The other equation with B's coordinates swapped h and k's places in the equation so it is also in correct.

Hope this helped!

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