Respuesta :

let's say the diameter of the larger gear is "x".

the small one has a diameter of 16cm, we know that, this is 2.5 more than (1/4)x.

[tex]\bf 16=\cfrac{1}{4}x+2.5\implies 16-2.5=\cfrac{x}{4}\implies 13.5=\cfrac{x}{4}\implies 4(13.5)=x \\\\\\ 54=x[/tex]

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