hello :
y = -3 |x + 2| -1
2 cas :
1 ) x+2 ≥ 0 ; |x + 2| = x +2
so : x ≥ -2 : y = -3 (x+2) -1
conclusion : y = -3x-7 when : x ∈
[-2 ; +∞[(two values of x in this itervall you have the graph)
2 ) x+2 ≤ 0 ; |x + 2| = - (x +2)
so : x ≤ -2 : y = -3 (-(x+2) ) -1
conclusion : y = 3x+5 when : x ∈ ] -∞ , -2 ] (two values of x in this itervall you have the graph)
look the graph :
