bailey48923 bailey48923

21-08-2017
Mathematics

contestada

What is the radius of a circle whose equation is x2 + y2 + 8x – 6y + 21 = 0?

Respuesta :

21-08-2017

x^2 + y^2 + 8x – 6y + 21 = 0
x^2 + 8x +16 + y^2 -6y +9 = -21 + 16 +9
(x+4)^2 + (y-3)^2 = 4
So the radius is 2

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lydialiliu lydialiliu

13-10-2020

Answer:

2 units

Step-by-step explanation:

edgenuity 2020

hope this helps!

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