bhhzd3578 bhhzd3578

21-08-2017
Chemistry

contestada

500 ml of .14 m naoh is added to 535 ml of .2 m weak acid (ka = 7.12 x 10^-5). what is the resulting ph?

Respuesta :

barnuts barnuts

04-09-2017

final concentration of NaOH = 0.14*500/(500+535) = 0.0676 M ( = concentration base)

final concentration of acid = 0.2*535/(500+535) = 0.1034 M - 0.0676 M = 0.0358

Therefore pH is:

pH = -log(7.12 x 10^-5) + log(0.0676/0.0358)

pH = 4.42

Answer Link

Otras preguntas

The diagram below shows the location of three stars in space. The light from Star 2 reaches Star 1 in 63 years. If Star 3 is 75 light years from Star 2, which o

Which energy source is formed when organic matter is trapped underground without exposure to air or moisture?

where did the framers meet to draft the constitution

What were the responsibilities of the satrap?

Which task was not one of the jobs of a scribe?

A recent scientific study of the land surrounding a large city has found a 40 percent decrease in forest area and 60 percent decrease in wildlife over ten years

how did manifest destiny affect slavery

defention of reversibily

Find the slope and the equation of the line through the points (-4,9) and(8,12)

how many liters are in five gallons