The equation of the circle is given by: (x-a)^2+(y-b)^2=r^2 where: (a,b) is the center of the circle given that the center of our circle is (-2,3) with the radius of 4, the equation will be: (x+2)^2+(y-3)^2=4^2 expanding the above we get: x^2+4x+4+y^2-6y+9=16 this can be simplified to be: x^2+4x+y^2-6y=16-13 x^2+y^2+4x-6y=3
