We can manipulate both equations in order to make them in terms of y, and then substitute it in.
[tex]y+3x=-5
\\4x+2y=-8
\\Manipulate \ the \ first \ one
\\ 3x = -y-5
\\ x = \frac{-y}{3}-\frac{5}{3}
\\ Substitute
\\ 4(\frac{-y}{3}-\frac{5}{3}) + 2y = -8
\\ Manipulate \ the \ second \ equation
\\ 4x = -2y-8
\\ x = \frac{-2y}{4}-2
\\ x = \frac{-y}{2}-2
\\ Substitute
\\ y+2(\frac{-y}{2}-2)=-5[/tex]
The answers are answer choice A and D
