Answer: x=4
Step-by-step explanation:
Given: QRST is a rectangle.
We know that in a rectangle, diagonals are congruent or equal.
Therefore, if QRST is a rectangle.
Then RT=SQ [diagonals of given rectangle]
Now substitute, [tex]RT=5x-5[/tex] and [tex]SQ = x + 11[/tex], then we have
[tex]5x-5=x+11\\\\\Rightarrow5x-x=11+5\\\\\Rightarrow4x=16\\\\\Rightarrow\ x=4[/tex]
Hence, the value of x = 4.
