Kau8fmsavansaudecur Kau8fmsavansaudecur
  • 22-05-2017
  • Chemistry
contestada

Calculate the molarity and the molality of an NH3 solution made up of 30.0 g of NH3 in 70.0 g of water. The density of the solution is 0.982 g/mL.

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JavierCollante
JavierCollante JavierCollante
  • 29-05-2017
the formula for molality---> m = moles solute/ Kg of solvent

the solute here is NH₃ because it's the one with less amount. which makes water the solvent.

1) let's convert the grams of NH₃ to moles using the molar mass

molar mass of NH₃= 14.0 + (3 x 1.01)= 17.03 g/ mol

30.0 g (1 mol/ 17.03 g)= 1.76 mol NH₃

2) let's convert the grams of water into kilograms (just divide by 1000)

70.0g= 0.0700 kg

3) let's plug in the values into the molality formula

molality= mol/ Kg---> 1.76 mol/ 0.070 kg= 25.1 m
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