[tex]\bf (\stackrel{x_1}{6}~,~\stackrel{y_1}{y})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-y}{10-6}=\stackrel{\stackrel{given}{\downarrow }}{\cfrac{1}{4}}\implies \cfrac{-1-y}{4}=\cfrac{1}{4} \\\\\\ 4(-1-y)=4\implies -1-y=\cfrac{4}{4}\implies -1-y=1\implies -2=y[/tex]
