xoxotrish16 xoxotrish16

26-02-2017
Mathematics

contestada

The lines whose equations are 2x + 3y = 4 and y=mx + 6 will be perpendicular when m is

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kristin14 kristin14

26-02-2017

2x+3y=4
-2x
3y=-2x+4
/3
y=-2/3x+4/3
next you would find the negative reciprical -3/2 so the m=-3/2

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abscisa15 abscisa15

26-02-2017

(d1): 2x+3y=4⇒ 3y = -2x+4 ⇒ y = (-2/3)x +4/3

(d2): y = mx+6

d1 || d2 ⇒ m = 3/2

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