Answer:
0.0625
Explanation:
The number of children in the family = 4
The possible combination of genders:
[tex]|\Omega|=2^4=16[/tex]The event that all are boys, |A|=1
Therefore, the probability that all are boys:
[tex]\begin{gathered} P(A)=\frac{1}{16} \\ =0.0625 \end{gathered}[/tex]