Respuesta :

[tex]\begin{gathered} SA=A1+A2+A3+A4+A5 \\ A1=A2=A \\ SA=A+A+A3+A4+A5 \\ SA=2A+A3+A4+A5 \\ A=\frac{(10in)(24in)}{2}=120in^2 \\ \\ A3=(24in)(13in)=312in^2 \\ A4=(10in)(13in)=130in^2 \\ A5=(x)(13in) \\ x=\sqrt{(24in)^2+(10in)^2} \\ x=26in \\ A5=(26in)(13in)=338in^2 \\ Hence \\ SA=2(120in^2)+312in^2+130in^2+338in^2 \\ SA=1020in^2 \\ The\text{ surface area is 1020in}^2 \end{gathered}[/tex]

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