[tex](\stackrel{x_1}{1}~,~\stackrel{y_1}{-2})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{4}-\stackrel{y1}{(-2)}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{1}}}\implies \cfrac{4+2}{2}\implies \cfrac{6}{2}\implies 3[/tex]
Answer:
3
Step-by-step explanation:
slope = y2-y1/x2-x1
from the question above,
X1= 1 Y1= -2
X2= 3 Y2= 4
SLOPE OF THE LINE
= 4--2/3-1
= 4+2/2
= 6/2= 3
slope of the line = 3
