jadeeee139 jadeeee139
  • 24-04-2022
  • Chemistry
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Calculate the molarity of 6.631 g NANO3 in 100.0 mL of solution


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aquanautsm aquanautsm
  • 24-04-2022

Answer:

0.7802 M

Explanation:

Data:

  • V (volume) = 100.0 mL → V = 0.1000 L
  • m (mass) = 6.631 g → n = 0.07802 mol

Wanted:

  • M (Molarity)

Equation:

M = [tex]\frac{mol}{L}[/tex]

Solution:

1. Convert mL to L:

  • V = 100.0 mL x [tex]\frac{1 L}{1000 mL}[/tex] = 0.1000 L

2. Convert g to mol:

  • n = [tex]\frac{6.631 g}{84.9947 g/mol}[/tex] = 0.07802 mol

3. Molarity Equation:

  • M = [tex]\frac{0.07802 mol}{0.1000 L}[/tex] = 0.7802 M
Answer Link
jsimpson11000 jsimpson11000
  • 24-04-2022

Answer:

Explanation:

Mole weight of NaNO3 ====> ~~ 85 gm

6.631 / 85   = # moles in .1 liter

6.631/85  / (.1)  = .78 M

Answer Link

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