Answer:
No.
Step-by-step explanation:
It's simpler than you might expect.
If [tex](x - 4)[/tex] is a factor, then it means that it the function [tex]f(x) = x^3 - 2x^2 + 5x + 1[/tex] can have [tex](x - 4)[/tex] factorised out.
This means that we can say [tex](x - 4) = 0[/tex]
Therefore [tex]x = 4[/tex]
If we put [tex]x = 4[/tex] into the equation:
[tex]f(4) = (4)^3 - 2(4)^2 + 5(4) + 1\\= 64 - 32 + 20 + 1\\= 53[/tex]
We didn't get 0, therefore it isn't a factor!
