midousuji
midousuji
26-01-2015
Mathematics
contestada
What's one of the factors of x² - x – 6 ?
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Аноним
Аноним
26-01-2015
[tex]x^2-x-6=x^2+2x-3x-6=x(x+2)-3(x+2)\\\\=\boxed{(x+2)(x-3)}[/tex]
The factors are: (x+2) and (x-3).
[tex]x^2-x-6=x^2+\underbrace{2x-3x}_{=-x}-6\\\\=\underbrace{x\cdot\boxed{x}}_{=x^2}+\underbrace{2\cdot\boxed{x}}_{=2x}+\underbrace{\fbox{-3}\cdot x}_{=-3x}+\underbrace{\fbox{-3}\cdot2}_{=-6}=\boxed{x}(x+2)+\fbox{-3}(x+2)\\\\=(x+2)(x+(-3))=\boxed{(x+2)(x-3)}[/tex]
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