dunlap2 dunlap2
  • 25-03-2022
  • Mathematics
contestada

HELP PLEASE!!!!
Find the tangent line approximation to 21/x near x = 21.

21/x≈

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Аноним Аноним
  • 25-03-2022

Answer:

y = -0.05x  + 2.05

Step-by-step explanation:

y = 21/x = 21x^-1

y' = -21x^-2 = -21/x^2

At x = 21 slope = -21/(21)^2 = -0.05 to nearest hundredth.

Tangent line is y - 1 = -0.05(x - 21)

y = -0.05x + 1.05 + 1

y = -0.05x  + 2.05

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