R=A2+B2+2ABcosβ−−−−−−−−−−−−−−−−√R=A2+B2+2ABcosβ
A=4NA=4N , B=3NB=3N , β=90°β=90° , cosβ=0cosβ=0
R=A2+B2−−−−−−−√R=A2+B2
R=42+32−−−−−−√=25−−√=5NR=42+32=25=5N
tanα=Bsin90°A+Bcos90°=34tanα=Bsin90°A+Bcos90°=34
α=37°α=37°
Therefore the resultant of the two forces has a magnitude of 5N5N and is at an angle of 37°37° with respect to
