samayiarobertso3363 samayiarobertso3363
  • 24-02-2022
  • Physics
contestada

A source charge generates an electric field of 1236 N/C at a distance of 4 m. What is the magnitude of the source charge? (Use k=) 2. 2 µC 680 µC 2. 2 C 680 C.

Respuesta :

leena
leena leena
  • 24-02-2022

Hi there!

The equation for the electric field of a point charge is given by:

[tex]E = \frac{kq}{r^2}[/tex]

E = Electric Field (N/C)
k = Coulomb's Constant

r = distance (m)

We can rearrange to solve for 'q':'

[tex]q^2 = \frac{Er^2}{k}\\\\q = \sqrt{\frac{Er^2}{k}}[/tex]

Plug in the values and solve:

[tex]q = \sqrt{\frac{(1236)(4^2)}{(8.99*10^9)}} = \boxed{0.00148 C}[/tex]

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