Respuesta :

  • Theta be A
  • sinA=1/4( sin has range -1 to 1 only)

cosA:-

[tex]\\ \rm\longmapsto \sqrt{1-sin^2A}=\sqrt{1-(1/4)^2}=\sqrt{1-1/16}=\sqrt{15/16}=\dfrac{3\sqrt{5}}{4}[/tex]

  • In Q1 all are positive

Now

[tex]\\ \rm\longmapsto sinA+cos^2A[/tex]

[tex]\\ \rm\longmapsto 1/4+15/16[/tex]

[tex]\\ \rm\longmapsto 4+15/16=19/16[/tex]

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