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22-01-2015
Mathematics

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What is the derivative of y= (x^2+4x+6)^5?

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konrad509 konrad509

22-01-2015

[tex] y= (x^2+4x+6)^5\\ y'=5(x^2+4x+6)^4\cdot(2x+4)\\ y'=10(x+2)(x^2+4x+6)^4[/tex]

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