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26-01-2022
Physics

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If a 2.00 kg ball is thrown straight upward with a KE of 500J. what maximum height will it reach?

Respuesta :

26-01-2022

Answer: 25.51m

Explanation: KEi +PEi = KEf + PEf

KEi = 500, PEi = 0, KEf = 0, PEf = 500

PE = fg * m * h

500 = 9.8 * 2 * h

h = 25.51m

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