23nathanshafero 23nathanshafero
  • 22-10-2021
  • Mathematics
contestada

need help with this plz

need help with this plz class=

Respuesta :

discipulus
discipulus discipulus
  • 23-10-2021

Answer:

[tex]x = \frac{ - 24 \pm \sqrt{ - 288} }{4} \\ = \frac{ - 24 \pm \sqrt{ ( - 1) {(12)}^{2} (2)} }{4} \\ = \frac{ - 24 \pm \sqrt{ - 1} \sqrt{ {12}^{2} } \sqrt{2} }{4} \\ = \frac{ - 24 \pm i 12\sqrt{2} }{4} \\ =-\frac{24}{4}\pm \frac{i12\sqrt{2}}{4}\\= - 6 \pm \: i3 \sqrt{2} [/tex]

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