Respuesta :

jessiluvsdance

Answer:

∆ACD≅∆BCD                              definition of a segment bisector

Step-by-step explanation:

I think this is the only way to prove it in one reason

clouter
DE=DE (common)
AE=BE (CE intersects AB)
And angle AED = angle BED
So triangle ADE ≅ triangle BDE
(SAS congruence rule)