From question we have,
- Inital velocity(u) = 0
- Accleration(a) = 15.4 m/s²
- Time taken(t) = 22 sec
Now, from the second equation of motion;
- s = ut + ½at² { where s = distance covered }
Just put all the values provided in the question, in this equation;
- s = ut + ½at²
- s = (0 × 22) + ½ × 15.4 × 22 × 22
- s = 15.4 × 11 × 22
- s = 15.4 × 242
- s = 3726.8 m
Therefore, distance it will rise in 22 seconds will be 3726.8m
