carebears2 carebears2
  • 22-08-2021
  • Mathematics
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What is the equation of a line perpendicular to y = -3x + 4 that passes through the point (-1, 6)?

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Аноним Аноним
  • 22-08-2021

Answer:

Equation is 3y = x + 19

Step-by-step explanation:

General equation:

[tex]y = mx + c[/tex]

For slope, m:

[tex]m_{1} \times m_{2} = - 1[/tex]

but m1 is -3:

[tex] - 3m_{2} = - 1 \\ m_{2} = \frac{1}{3} [/tex]

For y-intercept, c:

[tex]y = mx + c \\ 6 = ( - 1 \times \frac{1}{3} ) + c \\ \\ c = 6 + \frac{1}{3} \\ \\ c = \frac{19}{3} [/tex]

equation:

[tex]{ \sf{y = \frac{1}{3}x + \frac{19}{3} }} \\ \\ 3y = x + 19[/tex]

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