joshualcouchii joshualcouchii
  • 23-07-2021
  • Mathematics
contestada

Suppose f(x) = x^2. what is the graph of g(x)

Suppose fx x2 what is the graph of gx class=

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jimthompson5910 jimthompson5910
  • 23-07-2021

Answer:  g(x) = (1/16)*x^2

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Explanation:

Plug x = 4 into f(x) to find that f(4) = 16.

The output y = 16 drops to y = 1. We've multiplied by 1/16 to get this to happen.

In other words,

g(x) = (1/16)*f(x)

g(4) = (1/16)*f(4)

g(4) = (1/16)*16

g(4) = 1

So we can say that,

g(x) = (1/16)*f(x)

g(x) = (1/16)*x^2

and furthermore, we can say f(x) has been vertically compressed by a factor of 16.

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