Answer:
Solution given;
let dogs be d and cats be c.
according to the question
3 d +5 c =$365........[1]
5d+3c=$491.............[2]
By doing elimination method
multiplying equation 1 by 5 and equation 2 by 3 and subtracting
we get
15d+25c=$365*5
15d+9c=$491*3
- - -
____________
;16c=$352
c=[tex] \frac{352}{16} [/tex]=$22
the cost of one cat is $22.
