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25-05-2021
Mathematics

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What are the coordinates of the center of a circle with an equation of (x-3)^2y+7)^2=120?

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Аноним Аноним

25-05-2021

Answer:

Center = (3, -7)

Step-by-step explanation:

Standard form

(x - h)^2+ (y - k)^2 = r^2

Where (h, k) is the center

(x - 3)^2+ (y + 7)^2 = r^2

h = 3

k = -7

Center = (3, -7)

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