Selling price of 1st buffalo +Selling price of 2nd buffalo=20000 profit for 1st buffalo=0.05 of cost price of 1st buffalo loss for 2nd buffalo=0.1 of cost price of 2nd buffalo 1.05(cost price of 1st buffalo)+(0.9)cost price of 2nd buffalo=20000 the buffalo must cost must be same = x (say) 1.05x+0.9x=20000 1.95x=20000 x=10256.41 2x=20512.82 profit=20512.82-20000=512.82 profit %=2.56410 %