Te0en8Neelenamunod Te0en8Neelenamunod

21-11-2016
Mathematics

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find the limit as x approaches 0 of x/sin3x

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HomertheGenius HomertheGenius

22-11-2016

[tex] \lim_{x \to 0} \frac{x}{sin 3x} = \\ =\frac{0}{0}= \\ = \lim_{x \to 0} \frac{3x}{3sin3x} = [/tex]
= 1/3 ( because the limit as x approaches 0 of t/sin t = 1 ).

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