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22-10-2016
Chemistry

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Determine how many moles of ba(oh)2 are required to completely neutralize 0.445 mol of ch3cooh.

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Willchemistry Willchemistry

23-10-2016

mole ratio:

2 CH3COOH + Ba(OH)2 = Ba(CH3COO)2 + 2 H2O

2 moles CH3COOH -------------- 1 mole Ba(OH)2
0.445 moles CH3COOH --------- ??

0.445 x 1 / 2

=> 0.2225 moles of Ba(OH)2

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