The gas is most likely methane (CHâ‚„)
In general, the gas equation can be written Â
[tex]\large{\boxed{\bold{PV=nRT}}}[/tex]
where Â
P = pressure, atm Â
V = volume, liter Â
n = number of moles Â
R = gas constant = 0.08205 l.atm / mol K Â
T = temperature, Kelvin Â
[tex]\tt PV=\dfrac{mass}{M}RT\\\\M=\dfrac{mRT}{PV}=\dfrac{0.817\times 0.082\times 300}{1,00658\times 1.25}=15.97\approx=16[/tex]
So the gas is most likely methane (CHâ‚„ )