[tex]f(x) = 2x + 1[/tex]
[tex]y = 2x + 1[/tex]
Subtract sides -1
[tex]y - 1 = 2x + 1 - 1[/tex]
[tex]y - 1 = 2x[/tex]
[tex]2x = y - 1[/tex]
Divided sides 2
[tex] \frac{2}{2}x = \frac{y - 1}{2} \\ [/tex]
[tex]x = \frac{1}{2}y - \frac{1}{2} \\ [/tex]
Thus ;
[tex] {f}^{ - 1} = h(x) = \frac{1}{2}x - \frac{1}{2} \\ [/tex]
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So the correct answer is (( A )) .
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