1 amu=1.67×10
−27
kg
Using this and Einsteins relation, we get the energy equivalent to the rest mass as:
E=mc
2
=(1.67×10
−27
×0.0304)×(3×10
8
)
2
=4.569×10
−12
J
Converting this energy in electron volts.
E=
1.6×10
−19
4.569×10
−12
=28MeV
This is per nucleon of Helium. One Helium nucleus has four nucleons.
