Answer:
option 4
Step-by-step explanation:
Using the rule of radicals
[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] = [tex]\sqrt{ab}[/tex]
Given
(2 - 5[tex]\sqrt{6}[/tex] ) 3[tex]\sqrt{2}[/tex] ← distribute parenthesis by 3[tex]\sqrt{2}[/tex]
= 6[tex]\sqrt{2}[/tex] - 15[tex]\sqrt{12}[/tex]
= 6[tex]\sqrt{2}[/tex] - 15[tex]\sqrt{4(3)}[/tex]
= 6[tex]\sqrt{2}[/tex] - 15([tex]\sqrt{4}[/tex] × [tex]\sqrt{3}[/tex] )
= 6[tex]\sqrt{2}[/tex] - 15(2[tex]\sqrt{3}[/tex] )
= 6[tex]\sqrt{2}[/tex] - 30[tex]\sqrt{3}[/tex]
