Respuesta :

Answer:

2699.73661Ω or 2.697kΩ

Explanation:

[tex]V=IR[/tex]

So...

[tex]R=\frac{V}{I}[/tex]

So...

[tex]\frac{12.3}{0.004556} = 2699.73661[/tex]Ω

This is the answer, but the resistance is much too high for a circuit like this

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