Respuesta :

nktselepov

[tex]f(x) = -(x-1)^2 +4 \\ f(x) = - {x}^{2} + 2x + 3[/tex]

[tex]x_0 = \frac{ - b}{2a} \\ x_0 = \frac{ - 2}{2 \times ( - 1)} = 1[/tex]

[tex]y_0 = - {(1)}^{2} + 2 \times 1 + 3 = 4[/tex]

Answer: (1, 4)