Answer:
Yes
Step-by-step explanation:
f(x) = x^3 + x^2 −4x − 4
Factor by grouping taking x^2 out of the first group and -4 out of the second
0 = x^3 + x^2 −4x − 4
x^2(x+1) -4(x+1)
Factor out (x+1)
0=(x+1)(x^2-4)
Now we have the difference of squares
0=(x+1) (x-2)(x+2)
x+1 is a factor
