Answer:
50.62L
Explanation:
1torr= 0.00132atm
P=720torr = 0.95atm
V= 20°C= 20+273= 293K
PV=nRT
R=0.08206L-atm/mol-K
0.95×V= 2×0.08206×293
V= 2×0.08206×293/ 0.95
V= 50.62L
The volume should be 50.62L
Since
1 torr= 0.00132atm
Now
P=720torr = 0.95atm
So,
V= 20°C= 20+273= 293K
Now we know that
PV=nRT
here,
R=0.08206L-atm/mol-K
0.95×V= 2×0.08206×293
V= 2×0.08206×293/ 0.95
V= 50.62L
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