Answer: 5289 joules
Explanation:
The quantity of Heat Energy (Q) required to heat a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)
Thus, Q = MCΦ
Since, Mass of ice = 20 g
C is not provided (Recall that the specific heat capacity of ice is 2.010J/g°C)
Φ = (Final temperature - Initial temperature)
(120°C - (-25°C) =
120°C + 25°C = 145°C
Thus, Q = 20g x 2.010J/g°C x 145°C
Q= 5829J
Thus, 5829Joules of heat energy is required to heat ice
