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A set of cards contains four suits. Two suits are​ red, and two suits are black. In each suit there are cards numbered from 2 to 10 as well as a​ jack, a​ queen, a​ king, and an ace. Consider the following probability for one card selected at random.
​P(the selected card is a three or a red ​card)

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Answer: 7/13

Step-by-step explanation:

To do this, we find the probability of getting a black card, and getting a five but we have to subtract out the black fives.

There are 26 black cards out of the 52 cards in the set.

The are 4 fives out of the 52 cards in the set.

That would mean that 2 of the fives are black. If we didn't subtract the black fives, we would be overcounting.

Therefore we have 26/52 + 4/52 - 2/52 = 28/52 = 14/26 = 7/13