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Solve the following system of equations using Gaussian elimination method. If there are no solutions, type "N" for both xx, yy and zz. If there are infinitely many solutions, type "z" for zz, and expressions in terms of zz for xx and yy.-5x-7y-4z=-66x+2y+3z=-2-1x+2y-7z=0

Respuesta :

shejladautovic

Answer:

x=-224/229,

y=296/229,

z=118/229

Step-by-step explanation:

-5x-7y-4z=-6

6x+2y+3z=-2

-x+2y-7z=0...........( multiple with (-5) and sum with 1st equation, mult with 6 and                    sum with 2nd equation)

______________

-x+2y-7z=0

-17y+31z=-6.....(mult with 14)

14y-39z=-2.....(mult with -17) then sum

___________

-x+2y-7z=0

-229z=-118, so here we have z=118/229.

14y-39*(118/229)=-2, from here we have y=296/229

-x+2*(296/229)-7*(118/229)=0, we get that x=-234/229

In the same way you can do this in the matrix form>>

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