loren5341 loren5341
  • 24-11-2019
  • Mathematics
contestada

Find all real zeros of t
f(x)=x-14x² + 47x-18​

Respuesta :

dsouzaaww14
dsouzaaww14 dsouzaaww14
  • 30-11-2019

Answer:

x=3/7 and x= 3

Step-by-step explanation:

First simplify:

-14 x^2 +48x -18

divide everything by -2

-2(7 x^2 -24x +9) (Multiply the leading coefficient 7 by the constant 9)

-2 (x^2 -24x +63)

-2 [(x-3)(x-21)] Now divide the 7 that you multiplied earlier from 3 and 21

-2 [(x-3/7)(x-21/7)]

-2 [(7x-3)(x-3)]

Hence, the zeroes are 3/7 and 3

Hope this helps!

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