Answer: 1, 7, 1, 7, 1.
Step-by-step explanation:
The given function : [tex]f(n+1)=-2f(n)+8[/tex] and f(1) = 1 for n ≥ 1
We put value of n=1,2,3,4 , we get
For n=1 , [tex]f(2)=f(1+1)=-2f(1)+8=-1(1)+8=-1+8=7[/tex]
For n=2 , [tex]f(3)=f(2+1)=-2f(2)+8=-1(7)+8=1[/tex]
For n=3 , [tex]f(4)=f(3+1)=-2f(3)+8=-1(1)+8=7[/tex]
For n=4 , [tex]f(5)=f(4+1)=-2f(4)+8=-1(7)+8=1[/tex]
Hence, the first five terms of the given sequence are 1, 7, 1, 7, 1.
