Answer and explanation
We have given equation [tex]\frac{6x^3}{\sqrt[3]{27x^6}}[/tex]
We have to prove that after operation it will be equal to 2x
We know that cube root of 27 is 3
And cube root of [tex]x^6[/tex] is [tex]x^2[/tex]
So we can write the expression [tex]\frac{6x^3}{\sqrt[3]{27x^6}}=\frac{6x^3}{3x^2}=2x[/tex]
So after doing operation on the given expression the result will be 2x
Hence proved
