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21-10-2019
Physics

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A ball is thrown straight up and reaches a maximum height of 35m. Using 9.8m/s squared as gravity, what was the initial speed of the ball?

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MathPhys MathPhys

21-10-2019

Answer:

26.2 m/s

Explanation:

Given:

v = 0 m/s

Δy = 35 m

a = -9.8 m/s²

Find: v₀

v² = v₀² + 2aΔy

(0 m/s)² = v₀² + 2 (-9.8 m/s²) (35 m)

v₀ = 26.2 m/s

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